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Class XI Physics Oscillations 5
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Question 1
A particle executive a simple harmonic motion has a period of 6 sec. The time taken by the particle to move from the mean position to half the amplitude, starting from the mean position is
Question 2
The equation of a water is given by
Y = 10 sin .
If the displacement is 5 cm at t=0, then the total phase at t = 7.5 sec is
Y = 10 sin .
If the displacement is 5 cm at t=0, then the total phase at t = 7.5 sec is
Question 3
A particle executes SHM with amplitude 0.2 m and time period 24 s. The time required for it to move from the mean position to a point 0.1 m from the mean position is
Question 4
Two simple harmonic motions are represented by y1= 5[sin2πt+cos2πt] and y2 = 5sin.
The ratio of their amplitudes is
The ratio of their amplitudes is
Question 5
A particle of mass m is located in a one dimensional potential field where potential energy is given by V (x) = A (1 – cospx) , where A and p are constants .The period of small oscillations of the particle is
Question 6
A particle of mass m is attached to three identical massless springs of spring constant k as shown in the figure. The time period of vertical oscillation of the particles is
Question 7
A string is stretched between fixed points separated by 75.0 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. The lowest resonant frequency for these strings is
Question 8
What is the phase difference between two simple harmonic optionedpresented byx1=Asin and x2Acos()?
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Apr 4JEE & BITSAT