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ESE 2019: Machine Design Quiz-2
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Question 1
A truncated conical pivot bearing has semi-cone angle and the two radii are and respectively with . The coefficient of friction between the sliding surfaces is for an axial thrust load of WkN, the reduction in torque due to friction (assuming uniform rate of wear) is
Question 2
Considering the effect of centrifugal tension in a flat belt drive with T1 = tight side tension and Tc = centrifugal tension and m = mass per unit length of the belt, the velocity of the belt for maximum power transmission is given by _________.
Question 3
In rigid flanged coupling, bolts will connect two shafts that transmit power due to:
i. Shear force
ii. Bending moment
iii. Axial force
iv. Torsion moment
i. Shear force
ii. Bending moment
iii. Axial force
iv. Torsion moment
Question 4
In a gib and cotter joint, the gib and cotter are subjected to
Question 5
In a flat belt drive the maximum tension which the belt can be subjected to is T and the mass of the belt per unit length is m kg. The velocity of the belt for maximum power transmission is
Question 6
Match List-I (Application) with List-II (Joint) and select the correct answer using the code given below the lists:
List-I
A). Boiler shell
B). Marine Shaft Coupling
C). Crosshead and piston Rod
D). Automobile gear box (gears to shaft)
List-II
1). Cotter joint
2). Knuckle Joint
3). Riveted Joint
4). Splines
5). Bolted Joint
List-I
A). Boiler shell
B). Marine Shaft Coupling
C). Crosshead and piston Rod
D). Automobile gear box (gears to shaft)
List-II
1). Cotter joint
2). Knuckle Joint
3). Riveted Joint
4). Splines
5). Bolted Joint
Question 7
Stresses in a screw thread are estimated by considering the thread to be
Question 8
The maximum efficiency of a screw jack having square threads with friction angle is
Question 9
Match List-I with List-II and select the correct answer using the code given below the lists:
List-I
A). Unwin’s formula
B). Wahl factor
C). Reynold’s equation
D). Lewis from factor
List-II
1). Bearing
2). Rivets
3). gears
4). Springs
List-I
A). Unwin’s formula
B). Wahl factor
C). Reynold’s equation
D). Lewis from factor
List-II
1). Bearing
2). Rivets
3). gears
4). Springs
Question 10
A spring with 25 active coils cannot be accommodated within a given space. Hence 5 coils of the spring are cut. What is the stiffness of the new spring____?
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