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Revision Quiz | Binomial Theorem
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Question 1
The sum of the series
Question 2
The number of different terms in the expansion of is
Question 3
What is the co-efficient of x2 in the expansion of (1+4x+x2)1⁄2 is equal to?
Question 4
The number of natural numbers n in the interval [1005, 2010] for which the polynomial: 1 + x + x3 + x3 + ... + xn-1 divides the polynomial 1 + x2 + x4 + xt + ... + x2010 is
Question 5
Find the coefficient of in
Question 6
Find number of terms in
Question 7
In how many ways 10 identical oranges can be given to 3 children from 3 baskets having 7,6,4 oranges respectively?
Question 8
For x∈R, x≠-1 if
then a17 is equal to:
then a17 is equal to:
Question 9
The number of ways of selecting n things out of 3n things, of which n are of one kind and alike, and n are of a second kind and alike and the rest are unlike, is.
Question 10
Find the sum of the series
1+(0.2)+(0.2)2+(0.2)3+(0.2)4+(0.2)5+....
1+(0.2)+(0.2)2+(0.2)3+(0.2)4+(0.2)5+....
Question 11
Find the sum of the coefficients of (1+x
Question 12
If the coefficient of x3 and x4 in the expansion of (1 + ax + bx2) (1 – 2x)18 in powers of x are both zero, then (a, b) is equal to
Question 13
In the binomial expansion of (a – b)n, n ≥ 5, the sum of 5th and 6th terms is zero, then a/b equals
Question 14
Directions: Assertion–Reason type questions. Each of these questions contains two statements: statement–1 (Assertion) and Statement–2 (Reason). Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select the correct choice.
Statement–1:
nCr = (n + 2) 2n–1
Statement–2:
nCr xr = (1 + x)n + nx (1 + x)n–1
nCr = (n + 2) 2n–1
Statement–2:
nCr xr = (1 + x)n + nx (1 + x)n–1
Question 15
The coefficient of in is
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Dec 7JEE & BITSAT