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JEE 2020 Mathermatics : Area under the Curve - 01
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Question 1
The area of the region bounded by the curve y = x3, and the lines, y = 8, and x = 0, is
Question 2
The area under the curve y = |cos x – sin x|, and above x-axis is :
Question 3
The area between the curves xy = 3 and 2x + 3y = 9 is ( in metre square unit)
Question 4
If smaller area occupied by the curves with equation given below is A then Value of A/2 is-
Equation 1:
Equation 2:
Equation 1:
Equation 2:
Question 5
Find the area enclosed by the curve and
Question 6
Find the area bounded by the curve and the coordinates at
Question 7
Find the area enclosed by the curves and between the coordinates
Question 8
The curve x = 4-3y- cuts the y axis into two points P and Q. Then the area enclosed by the y axis and the portion of the curve which lies between P and Q is?
Question 9
Let f:R→R be a function such that f(2-x)=f(2+x) and f(4-x)=f(4+x), for all x∈R and
Then the value of
is:
Then the value of
is:
Question 10
The area bounded by the curve y = x (3 – x)2 , the x – axis and the ordinates of the maximum and minimum points of the curve is
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Jun 5JEE & BITSAT