Most Exclusive Questions on Geometry for SSC CGL Tier-II Exam. As you know, SSC CGL Tier-II exam is going to be held across India from 11-13th September. You all must be busy in your preparation for the D-Day. Geometry is one of the most imp topics which is very important from the examination's perspective. You can expect around 10-12 questions from this topic in your exam. To help you in your preparation, we have selected some exclusive questions on Geometry that will act as an icing on the cake. We have also provided a detailed solution below each question to help you with the method or approach.
Most Exclusive Questions on Geometry for SSC CGL Tier-II Exam
1. In ∆ABC, E is a point such that BE is an angle bisector of ∠B & AE ⊥ BE. F is a point on AC such that EF || BC. If AC = 12 cm, find the length of AF.
A. 8 cmB. 4 cm
C. 9 cm
D. 6 cm
We know in an isosceles triangle ABC
If AD ⊥BC then, AD is angle bisector of A or vice versa
∴ here since BE is angle bisector and BE ⊥ AD.
∴ ∆ABD is an isosceles ∆ where AB = BD
Also BE is bisecting AD at E
∴ By Thales theorem, EF || CD
∴ F is also the mid-point of AC
Hence, length of AF cm
2.In the given figure and are the centers of two circles of same radius R. A third circle of center and radius is tangent to both circles. If distance between and is thrice of radius of smaller circle, find the distance between and the line
A.
B.
C.
D.
3.In the given figure there is ABC . D is a point on BC. BAD = 30 and CAD = 60. Find the length of side AD .
A.
B.
C.
D.
Area of triangle = AB.AC sin . Where is angle between AB and AC.
Area of triangle ABC = Area of triangle ABD + Area of triangle DAC
AD =
4.ABCD is a quadrilateral which circumscribed a circle of radius 7 cm. AB||CD, and . What is the perimeter of quadrilateral?
A.B.
C.
D.
OB is the angle bisector of angle B.
Again,
Perimeter
5.ABCD is a rectangle. P is a point inside the rectangle such that AP = 3 cm, PC = cm and DP = 5 cm. If what is the length AB of the rectangle?
A. 7 cmB. cm
C.
D. cm
Since APB is a right triangle,
6.There are two identical circles of radius 4 cm each. If the length of the direct common tangent is 14 cm, then what is the length of the transverse common tangent?
A.B.
C.
D.
Since, both circles are identical, AB = OM = 14 cm. and OC = CM = 14/2 = 7 cm. Now. OPC and CQM are right triangles and congruent also.
7.In the given figure ABC is a right triangle with and If the radius of the larger circle is 6 cm, what is the radius of smaller circle?
A. 4 cm
B. 3 cm
C. 1 cm
D. 2 cm
OC will be angle bisector of C.
Now,
8.What is the ratio of the inradius, circumradius and one of the ex-radii of an equilateral triangle?
A. 1:2:3B. 1:2:5
C. 2:3:5
D. 1:2:4
Property: Ratio between the inradius, circumradius and ex-radius is 1:2:3.
9.ABC is a triangle such that AB = AC. BD and CE are the medians to the sides AC and AB respectively. If BD⊥CE, then value of AB/BC =?
A.B. 2/√3
C. 4/3
D. 3/2
ABC is an isosceles triangle, BE = CD=AB/2 = AC/2 and BD = EC and hence BO = OC, OE = OD. Also, ED=BC/2 Now,
2 BE2 = 5 BC2/4
2AB2/4 = 5BC2/4
AB/BC =
10.In the given figure PA=10,RC=X and QB = 15, Find the value of X.(PAB=QBC=RCB=90)
A. 6
B. 10
C. 8
D. 12
In BAP and BCP
------- (1)
In ARC and AQB
-------- (2)
Adding equation (1) and (2)
1015 = 10x + 15x
x =
11.If two opposite vertex in a rectangle are (2,1) and (5,3) and the equation of other diagonal is x-2y+k=0. find k?
A. 1/2B. 3/2
C. 2
D. 6
M is the mid-point of diagonal AC & BD .
Co-ordinate of M =
line x-2y+k passes through M(7/2,2)
hence
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