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GATE 2020 : Computer Networks Quiz 10

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Question 1

Consider the following plot of TCP window size as a function of time. Assume TCP is operating with slow start , congestion avoidance , fast retransmit and fast recovery mechanism.

What is the time interval where the slow start runs again because of time out and because of 3 ACKS's respectively ?

Question 2

Consider the following statements regarding the slow start phase of the TCP congestion control algorithm. Note the stands for the TCP congestion window and MSS denotes the Maximum Segment Size.
i. The increases by 2 MSS on every successful acknowledgement.
ii. The approximately doubles on every successful acknowledgment.
iii. The increases by 1 MSS every round trip time.
iv. The approximately doubles every round trip time.
Which one of the following is correct?

Question 3

TCP congestion window size (cwnd) is adjusted differently in “slow start” and “congestion Advoidance”. Which of the following is their respective expression for cwnd?

Question 4

Consider the size of congestion window of a TCP connection be 36 KB when a timeout occurs. The RTT for the connection is 200 microseconds and the maximum segment size is 2KB. What is the time taken by the TCP connection to get back to 36 KB congestion window ?

Question 5

Host A sends a UDP datagram containing 8880 bytes of user data to host B over an Ethernet LAN. Ethernet frames may carry data up to 1500 bytes (i.e. MTU=1500 bytes). Size of UDP header is 8 bytes and size of IP header is 20 bytes. There is no option field in IP header. How many total number of IP fragments will be transmitted and what will be the contents of offset field in the last fragment?

Question 6

The initial congestion window size over a TCP is 1. If slow strat algorithm is used and the size of congestion window incremented by 1 whenever an ACK is received i.e. after first round trip time congestion window size is 2 segments. Assume connection never leaves slow start. Find the number of RTT’s to send 3999 segments.
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Jun 2GATE & PSU CS