Study Notes for CAT 2021: Geometric Progression

By Gaurav Gupta|Updated : May 7th, 2021

Geometric Progression

A sequence is said to be in Geometric Progression, if the ratio between any two adjacent numbers in the sequence is constant (non zero). This constant is said to be common ratio (c.r.)

e.g. 1, 2, 4, 8 ..........…… c.r. = 2

1, 1/2, 1/4, 1/8, …..……… c.r. = 1/2

1/4, –1/2, 1, –2, 4, ……… c.r. = –2

 

Geometric Progression

A sequence is said to be in Geometric Progression, if the ratio between any two adjacent numbers in the sequence is constant (non zero). This constant is said to be common ratio (c.r.)

e.g. 1, 2, 4, 8 ..........…… c.r. = 2

1, 1/2, 1/4, 1/8, …..……… c.r. = 1/2

1/4, –1/2, 1, –2, 4, ……… c.r. = –2

In general

a, ar, ar2, ar3, ……, a rn–1

By close inspection of the above series we can say the n-th term of GP will be given by

tn = arn–1

Sum of a geometric progression

Now, let us try to find out the sum of the first n terms of a G.P.

Sn = a + ar + ar2 +…+ arn–1 … (6)

Multiplying both sides by r, we get,

rSn = ar + ar2 +…+ arn–1 + arn … (7)

Subtracting (7) from (6), we have

Sn – rSn = a – arn

or, Sn = a(1–rr)/(1–r) … (8)

From equation (8) sum of n terms of a G.P.

Sn = a(1–rr)/(1–r)

Basically we have to find out the value of particular case when, n tends to infinity.

If we take any value of |r| greater than 1 then value of rn when n → ∞ will tend to infinite. Hence value of S will also tend to infinite. If we take of |r| less than rn when n → ∞ will tend to zero. (take any number greater than 1 multiply it by itself several time. Are you getting convinced that it will tend to infinity. Do the same exercise with one another number less than 1).

Thus S- = a/1–r for |r| < 1 … (9)

Enquiry: What happens when any real number can be add subtract, multiply and divides to each term of a geometric series?

  1. Multiplication/Division by a constant number to each term of a G.P. also results a G.P.
    Suppose a1, a2, a3, ……, an are in G.P.
    then ka1, ka2, ka3, ……, kan and
    a1/k, a2/k, ... ... ... an/k will also be in G.P.
    Where k ? R and k ≠ 0.
  1. Multiplication/Division of two G.P.’s also results a G.P.
    Suppose a1, a2, a3, ……, an
    and b1, b2, b3, ……, bn are two G.P.
    then a1b1, a2b2, a3b3, ……, an bn
    then a1/b2, a2/b2, ... ... ..., an/bn will also be in G.P.
  1. Reversing the order of a G.P.’s also results a G.P.
    Suppose a1, a2, a3, ……, an are in G.P.
    then an, an–1, an–1, ……, a3, a2, a1 will also be in G.P.
  1. Taking the inverse of a G.P. also results a G.P.
    Suppose a1, a2, a3, ……, an are in G.P.
    then 1/a1, 1/a2, 1/a ……, 1/an will also be in G.P.

Note: Students are suggested to assume the known variable related to geometric progression in following way.

Three number in G.P. ∴ α/ß, α, αß c.r = ß

Four number in G.P. ∴ α/ß3, α ß, αß, αß3 c.r. = ß2

Five numbers in G.P. ∴ α/ß2, α/ß, α . αß . αß2 c.r. = ß

Summary of Important Notes:

  • If each term of a G.P. is multiplied (or divided) by a fixed non-zero constant, then the resulting sequence is also a G.P. with same ratio as that of the given G.P.
  • If each term of a G.P. (with common ratio r) is raised to the power k, then the resulting sequence is also a G.P. with common ratio rk.
  • If a1, a2, a3, ……, b1, b2, b3, …… are two G.P.’s with common ratios r and r’ respectively then the sequence a1b1, a2b2, a3b3, …… is also a G.P. with common ratio rr’.
  • If we have to take three terms in a G.P., it is convenient to take them as a/r, a, ar. In general, we take a/rk, a/rk–1, …, a, ar, …, ark in case we have to take (2k + 1) terms in a G.P.
  • If we have to take four terms in a G.P., it is convenient to take them as a/r3, a/r, ar, ar3. In general, we take a/r2k–1, a/r2k–3, ... ... ... a/r, ar, ……, ar2k–1, in case we have to take 2k terms in a G.P.
  • If a1, a2, ……, an are in G.P., then a1an = a2an–1 = a3an–2 = ……
  • If a1, a2, a3, …… is a G.P. (each a1 > 0), then loga1, loga2, loga3 …… is an A.P. The converse is also true.

Geometric mean between two numbers

If three numbers are in G.P. then middle one is said to be geometric mean (GM) of two others.

Let, G be the geometric mean between two number a and b

So, a G b are in G.P.

G/a = b/G.

or, G2 = ab

∴ G =√ab

Similarly we can find two geometric means between two given numbers a and b.

Let a, G1, G2, b are in G.P.

tn = a rn–1

or b/a = r3

r =(b/a)1/3

G1 = ar2 = a (b/a)1/3 = a1/3 b2/3

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