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Approximation & Quadratic Equation II Quantitative Aptitude II MH-CET 2021 II 15 July

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Question 1

Direction: What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value.

Question 2

Direction: What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value).
55.009 × 47.993 – ?% of 8001.008 = (11.994)3 + 67.896 × 3.985

Question 3

Direction: What will come in place of question mark (?) in the following question (You do not have to calculate the exact value)?
(4.023)+ (29.997)2 − 78.024 × 2.978 − 112.998 = ?

Question 4

Direction: What approximate value should come in place of the question mark (?) in the following equation (Note: You are not expected to calculate the exact value)?
√960.87 × √1850 + 60.09% of 2535.112 + 831.94 ÷ 13 – 342 = ?

Question 5

Direction: What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)
[(57.95)2 − (20.97)2] ÷ ? = (52.06)2 + (16.92)2

Question 6

Direction: In the following question, two equations are given in variables x and y. You have to solve these equations and determine relation between x and y.
I. 3x2 – (6 + √5)x + 2√5 = 0

II. 8y2 – (16 + 3√5)y + 6√5 = 0

Question 7

Direction: Solve the given quadratic equations and mark the correct option based on your answer—
I. x² − 16x + 64 = 0
II. y² − 16y + 63 = 0

Question 8

Direction: Solve the given quadratic equations and mark the correct option based on your answer.
I.  
𝐈𝐈.

Question 9

Direction: In the following question two equations are given in variables p and q. You have to solve these equations and determine the relation between p and q.
I. 3p2 – 23p + 40 = 0
II. 2q– 23q + 66 = 0

Question 10

Direction: In the following question two equations are given in variables x and y. You have to solve these equations and determine the relation between x and y.
I. 15x2 − 11x + 2 = 0
II. 10y2 − 9y + 2 = 0
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